Ione faraday of electricity will liberate one gram atom of a metal from a solution of
A. `AuCl_(3)`
B. `CuSO_(4)`
C. `BaCl_(2)`
D. `KCl`

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Correct Answer - D
`KCl hArr K^(+) + Cl^(-)` and `K^(+) + e^(-) rarr K`
Thus, one mole `KCl` need one mole electrons to liberate one gram metal atom. One mole electron charge is equal to `96500 C (1 F)`. Hence, `1 F` charge will liberate one gram atom of metal from solution of `KCl`,

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