The elevation in boiling point would be highest for
The elevation in boiling point would be highest for
A. `0.08 m BaCl_(2)`
B. `0.10 m` glucose
C. `0.10 m KCl`
D. `0.06 m` calcium nitrate
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Correct Answer - a
More the number of particles and concentration higher is the elevation in boiling point. Thus, 0.08 m KCl
`= -0.082xx2 = 0.24m` (highest)
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