Higher oxidation state of manganese in fluoride is `+4 (MnF_(4))` but highest oxidation state in oxides is `+7(Mn_(2)O_(7))` because
Higher oxidation state of manganese in fluoride is `+4 (MnF_(4))` but highest oxidation state in oxides is `+7(Mn_(2)O_(7))` because
A. fluorine is more electronegative than oxygen
B. fluorine does not posses d- orbitals.
C. fluorine stabilises lower oxidation state.
D. In covalent compounds fluorine can form single bond only while oxygen forms double bond.
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Correct Answer - D
Fluorine can form single bond only white `O_(2)` forms double bonds.
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