Equivalent conductane of 0.1 M HA (weak acid) solution is 10 S`cm^(2) "equivalent"^(-1)` and that at infinite dilution is 200 S `cm^(2) " equivalent"^
Equivalent conductane of 0.1 M HA (weak acid) solution is 10 S`cm^(2) "equivalent"^(-1)` and that at infinite dilution is 200 S `cm^(2) " equivalent"^(-1)` Hence pH of HA solution is
A. 1.3
B. 1.7
C. 2.3
D. 3.7
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Correct Answer - C
`alpha=(^^_(C))/(^^_(eq))=(10)/(200)=(1)/(20)=0.05`
`[H^(+)]=c.alpha,=0.1xx0.05=5xx10^(-3)`
`thereforepH=2.3`
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