The EMF of the cell `Ni|Ni^(2+)` (0.01M)
`Cl^(-)(0.01M)//Cl_(2)`, pt is__ V if the SRP of nickel and chlorine electrodes are `-0.25` and `+1.36 V` respectively
A. `+1.61`
B. `-1.61`
C. `+1.79`
D. `-1.79`

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1 Answers

Correct Answer - C
`E_(cell)=E^(@)cell-(0.059)/2 log[Ni^(2+)][Cl^(-)]^(2)`

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