`alpha`-chloropropanoic acid on treatment with alcoholic acid KOH followed by acidification gives :
A. `CH_(3)-CH(OH)-CO OH`
B. `CH_(2)=CH-CO OH`
C. `HO-CH_(2)-CH_(2)-CO OH`
D. `CH_(3)-CH_(2)-CO OH`

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Correct Answer - 3
`CH_(3)CHClCO OH overset(alc KOH)toCH_(2)=CHCO OH`

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