A reaction takes place in three steps. The rate constant are `k_(1), k_(2)` and `k_(3)`. The overall rate constant `k=(k_(1)k_(3))/(k_(2))`. If `E_(1)
A reaction takes place in three steps. The rate constant are `k_(1), k_(2)` and `k_(3)`. The overall rate constant `k=(k_(1)k_(3))/(k_(2))`. If `E_(1), E_(2)` and `E_(3)` (energy of activation) are 60, 30 and 10 kJ, respectively, the overall energy. Of activation is
A. 40 kJ
B. 30 kJ
C. 400 kJ
D. 300 kJ
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Correct Answer - A
`k_(1)=Ae^(-E_(a_(1))//RT),k_(2)=Ae^(-E_(a_(2))//RT),k_(3)=Ae^(-E_(a_(3))//RT)`
Overall rate = `k=(k_(1)k_(3))/(k_(2))`
Therefore, overall `E_(a)=E_(a_(1))+E_(a_(3))-E_(a_(2))`
`=60 +10 -30 =40 kJ`
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