Find the maximum magnitude of the linear momentum of a photoelectron emitted when light of wavelength 400 nm falls on a metal having work function 2.5e V.

4 views

1 Answers

Correct Answer - `(P^(2))/(2m)((1.24xx10^(4))/(4000)-2.5)eV=0.6eV`
`P=sqrt(2xx9.1xx10^(-31)xx0.6xx1.6xx10^(-19))`
`=4.2xx10^(-25)kg.m//s`

4 views

Related Questions