A radiation of wave length `2500A^(0)` is incident on a metal plate whose work function is `3.5eV`. Then the potential required to stop the fastest photo electrons emitted by the surface is `(h=6.63xx10^(-34)Js & c=3xx10^(8)m//s)`
A. `1.86V`
B. `3.00V`
C. `1.46V`
D. `2.15V`

4 views

1 Answers

Correct Answer - C
`V_(0)e=[(12400)/(lambda "in"A^(0))-omega_(0)]eV`

4 views

Related Questions