A 280 days old radioactive substance shows an activity of 6000 dps, 140 days later it’s activity becomes 3000 dps. What was its initial activity 

(A) 20000 dps 

(B) 24000 dps 

(C) 12000 dps 

(D) 6000 dps

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1 Answers

Correct option (B) 24000 dps 

Explanation:

A1 = λN1 = λN0e−λt1

A2 = λN2 = λN0 e−λt2 

and A0 = λN0 = 24000 dps.

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