A 0.2 m aqueous solution of KCl freezes at -0.68°C. Calculate ‘i’ and the osmotic pressure at 0°C.
A 0.2 m aqueous solution of KCl freezes at -0.68°C. Calculate ‘i’ and the osmotic pressure at 0°C. Assume the volume of solution to be that of pure H2O and Kf for H2O is 1.86 K Kg/mol.
5 views
1 Answers
(ΔTf)normal = Kf x m = 1.86 x 0.2= 0.372
i= Observed colligative property/Normal colligative property
= 0.68/0.372
Observed osmotic pressure= i x Normal osmotic pressure
= i x c RT
= 1.83 x 0.2 x 0.082 x 273
= 8.2 atm
5 views
Answered