If the lattice parameter for a crystalline structure is 3.6 A, then the atomic radius in fcc crystal is

(a) 2.92 A

(b) 1.27 A

(c) 1.81 A

(d) 2.10 A

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1 Answers

The correct option is (b) 1.27 A.

Explanation:

The atomic radius in a f c.c. crystal is a/2√2

where a is the length of the edge of the crystal.

Atomic radius = 3.6 A/ 2√2 = 1.27 A.

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