An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%.
An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be
(a) CHO
(b) CH4O
(c) CH3O
(d) CH2O
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The correct option : (c) CH3O
Explanation :
| Element | % | Atomic mass | mole ratio | simple ratio |
| C | 38.71 | 12 | 38.71/12 = 3.22 | 3.22/3.22 = 1 |
| H | 9.67 | 1 | 9.67/1 = 9.67 | 9.67/3.22 = 3 |
| O | 51.62 | 16 | 51.62/16 = 3.22 | 3.22/3.22 = 1 |
Hence empirical formula of the compound would be CH3O.
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