Sum of the ages of a father and the son is 40 years. If father's age is three times that of his son, then find their respective ages.
Sum of the ages of a father and the son is 40 years. If father's age is three times that of his son, then find their respective ages.
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Let age of father and son be x and y respectively.
x + y = 40 ...(i)
x = 3y ...(ii)
By solving eqns. (i) and (ii), we get
x = 30 and y = 10
Ages are 30 years and 10 years respectively.
Detailed Answer :
Let age of father and son be x and y years respectively.
x + y = 40 ...(i)
x = 3y ...(ii)
Substitute the value of x from eqn. (ii) in, (i)
3y + y = 40
⇒ 4y = 40
y = 10 yrs.
From (i), x + 10 = 40
x = 30 yrs.
Age of father is 30 years and age of son is 10 years.
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