Nichrome and copper wires of same length and same radius are connected in series. Current I is passed through them. Which wire gets heated up more ? Justify your answer.

7 views

2 Answers

H= I2RNt

HN/HC=RN/RR

HC=I2RCt

RN>RC

So, HN>HC

7 views

Nichrome wire gets heated up more.

Heat dissipated in a wire is given by

\(H=I^2Rt\)

\(H=I^2 \,\frac{pl}{A}t\) \((\because\,R=\frac{pl}{A})\)

Here, radius is same, hence area (A) is same. Also, current (I) and length (l) are same.

\(\therefore \,H\infty\,r\)

But Pnichorme > Pcopper

∴ Hnichrome > Hcopper

7 views