Straight lines 2x + y = 5 and x - 2y = 3 intersect at the point A . Points B and C are chosen on these two lines such that AB = AC .
Straight lines 2x + y = 5 and x - 2y = 3 intersect at the point A . Points B and C are chosen on these two lines such that AB = AC . Then the equation of a line BC passing through the point (2, 3) is
(A) 3x - y - 3 = 0
(B) x + 3y - 11 = 0
(C) 3x + y - 9 = 0
(D) x - 3y + 7 = 0
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(A) 3x - y - 3 = 0
(B) x + 3y - 11 = 0
[Hint: Note that the lines are perpendicular . Find the equation of the lines through (2, 3) and parallel to the bisectors of the given lines, the slopes of the bisectors being - 1/3 and 3 ]
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