Vertical angles of two isosceles triangles are equal. If their areas are in the ratio 16 : 25,
Vertical angles of two isosceles triangles are equal. If their areas are in the ratio 16 : 25, then find the ratio of their altitudes drawn from vertex to the opposite side.
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Could you explain how the area(ABC)/area(PQR) = AD^2/PE^2......
Because the theorem states that the ratio of areas of similar triangles is equal to the square of ratios of its corresponding sides but AD and PE are not sides of the triangles .... they are altitudes.....
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