A bag contains 5 red,8 green and 7 white balls. One ball is drawn at random from the bag, find the probability of getting :
A bag contains 5 red,8 green and 7 white balls. One ball is drawn at random from the bag, find the probability of getting :
(i) not a white ball,
(ii) neither a green nor a red ball.
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Total balls = 5 + 8 + 7 = 20
(i) P(white ball) = 7/20
P(not white) = 1 - 7/20 = 13/20
(ii) P(green or red) = (8 + 5)/20 = 13/20
P(neither green nor red) = 1 - (13/20)
= 7/20
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