Two different dice are tossed together. Find the probability : (i) of getting a doublet (ii) of getting a sum 10, of the numbers on the two dice.
Two different dice are tossed together. Find the probability :
(i) of getting a doublet
(ii) of getting a sum 10, of the numbers on the two dice.
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(i) Probability of getting a doublet when two
different dice are tossed. then
Total events n(S) = 6 x 5 = 36
Favourable events i.e., to getting doubtets
E = {(1, 1), (2,2), (3,3), (4,4),
(s,s), (6,6)
n(E) = 6
Probability of getting a doubtets
n(E) / n(s) = 6 / 36 = 1 / 6
Probability of getting a doublets = 1/ 6
(ii) Favourable events of getting a sum 10, of the numbers on the two dice
E = {(4 , 6),(5,5),(6,4)}
n(E) = 3
Probability of getting a sum 10, of the numbers on the two dice = n(E) / n(S)
= 3 / 36 = 1 / 12
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