The difference between two numbers is 26 and one number is three times the other. Find the numbers.

Let the larger number be x and the smaller number be y. Then, we have: 

x –y = 26 ………….(i) 

x = 3y …………(ii) 

On substituting x = 3y in (i), we get: 

3y –y = 26 

⇒ 2y = 26 

⇒ y = 13 

On substituting y = 13 in (i), we get: 

x – 13 = 26 

⇒ x = 26 + 13 = 39 

Hence, the required numbers are 39 and 13.

Let the numbers are x and y. 

Given that one number (let x) is three times the other (y). 

i.e., x = 3y ⇒ x – 3y = 0. ... (1) 

Given that the difference between both numbers is 26. 

i.e., x – y = 26. ... (2) 

Now subtracting equation (2) from equation (1), we get,

(x – 3y) – (x – y) = 0 – 26 

⇒ – 2y = – 26 ⇒ y = \(\frac{26}{2}\)= 13. 

Now putting the value of y = 13, in equation (2), 

we get x – 13 = 26 

⇒ x = 26 + 13 = 39.

Hence, the required number are 13 and 39.

Let the bigger number is x and smaller number is y. 

Given that difference between both numbers is 26. 

∴ x – y = 26. … (1) 

Given that one number is three times the other 

Therefore, x = 3y. … (2) 

Now, putting x = 3y in equation (1), we get 3y – y = 26 

⇒ 2y = 26 ⇒ y = \(\frac{26}{2}\) = 13. 

Now, putting y = 13 in equation (2), we get 

x = 3 × 13 = 39.

Hence, the numbers are 13 and 39.

Let the larger number be x and the smaller number be y. 

Then, we have: 

x –y = 26 ………….(i) 

x = 3y …………(ii) 

On substituting x = 3y in (i), we get: 

3y –y = 26 ⇒ 2y = 26 ⇒ y = 13 

On substituting y = 13 in (i), we get: 

x – 13 = 26 ⇒ x = 26 + 13 = 39 

Hence, the required numbers are 39 and 13.