Taxi charges in a city consist of fixed charges per day and the remaining depending upon the distance travelled in kilometers.

Let fixed charges be Rs.x and rate per km be Rs.y. 

Then as per the question 

x + 80y = 1330 ………(i) 

x + 90y = 1490 ……..(ii) 

Subtracting (i) from (ii), we get 

10y = 160 

⇒ y = 160/10 = 16 

Now, putting y = 16, we have 

x + 80 × 16 = 1330 

⇒x = 1330 – 1280 = 50 

Hence, the fixed charges be Rs.50 and the rate per km is Rs.16.

Let fixed charge = Rs. x

and charge per kilometer = Rs. y

According to the question,

x + 110y = 690 …(i)

and x + 200y = 1050 …(ii)

On subtracting Eq. (i) from Eq. (ii), we get

x + 200y – x – 110y = 1050 – 690

⇒ 90y = 360

⇒ y = 40

On putting the value of y = 40 in Eq. (i), we get

x + 110(40) = 690

⇒ x + 440 = 690

⇒ x = 690 – 440 = 250

Hence, monthly fixed charges is Rs. 250 and charge per kilometer is Rs. 40