Find a fraction which becomes ( 1/2 ) when 1 is subtracted from the numerator and 2 is added to the denominator, and the fraction becomes ( 1/3 ) when 7 is subtracted from the numerator and 2 is subtracted from the denominator.

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1 Answers

Let the required fraction be x/y . 

Then, we have: x−1/ y+2 = 1/2 

⇒ 2(x – 1) = 1(y + 2) 

⇒2x – 2 = y + 2 

⇒2x – y = 4 ……(i) 

Again, x−7/ y−2 = 1/3 

⇒3(x – 7) = 1(y – 2)

⇒3x – 21 = y – 2 

⇒ 3x –y = 19 ……(ii) 

On subtracting (i) from (ii), we get: 

x = (19 – 4) = 15 

On substituting x = 15 in (i), we get: 

2 × 15 – y = 4 

⇒ 30 – y = 4 

⇒y = 26 

∴ x = 15 and y = 26 

Hence, the required fraction is 15/26

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