A circular coil of wire consisting of 100 turns, each of radius 8.0 cm carries current of 0.40 A. What is the magnitude of the magnetic field B at the center of the coil? 

4 views

1 Answers

B = μ0NI/2R = μ0 x 100 x 0.4/2 x 8 x 10-2 = 3.1 x 10-4 T

4 views