The equation of the line passing through the point (1,2) and perpendicular to the line x+y + 1 = 0 is
The equation of the line passing through the point (1,2) and perpendicular to the line x + y + 1 = 0 is
(A) y – x + 1 = 0
(B) y – x – 1 = 0
(C) y – x + 2 = 0
(D) y – x – 2 = 0
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Answer is (B)
Slope of the given line +1=0 is-1.
So, slope of line perpendicular to above line is 1.
Line passes through the point (1,2).
Therefore, equation of the required linens:
y-2 = 1(x- 1) => y-x-1=0.
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