The first four terms of an AP, whose first term is –2 and the common difference is –2, are
The first four terms of an AP, whose first term is –2 and the common difference is –2, are
(A) – 2, 0, 2, 4
(B) – 2, 4, – 8, 16
(C) – 2, – 4, – 6, – 8
(D) – 2, – 4, – 8, –16
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(C) – 2, – 4, – 6, – 8
Explanation:
First term, a = – 2
Second Term, d = – 2
a1 = a = – 2
We know that the nth term of an AP is
an = a + (n – 1)d
Where,
a = first term
an is nth term
d is the common difference
Hence, we have,
a2 = a + d = – 2 + (- 2) = – 4
Similarly,
a3 = – 6
a4 = – 8
So the A.P is
– 2, – 4, – 6, – 8
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