If the circles x^2 + y^2 + 4x + 22y + c = 0 bisects the circumference of x^2 + y^2 – 2x + 8y – d = 0
If the circles x2 + y2 + 4x + 22y + c = 0 bisects the circumference of x2 + y2 – 2x + 8y – d = 0 then c + d equal
(1) 60
(2) 50
(3) 40
(4) 56
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