A uniform chain of mass m and length l is lying on a table with l/4 of its length hanging freely from the edge of the table.
A uniform chain of mass m and length l is lying on a table with l/4 of its length hanging freely from the edge of the table. The amount of work done in dragging the chain on the table completely is :–
(a) mgl/4
(b) mgl/8
(c) mgl/32
(d) mgl/16
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Correct option (c) mgl/32
Explanation:
Mass of (l/4) length of the chain = m/4
The weight of this part of the chain acts as its CG which is at a distance (L/8) from the edge of the table.
Work done = (m/8) g (L/8) = mgl/32
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