In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system
In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system. [ Assume π = 22/7 ]
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Height (h) of cylindrical pipe = Length of cylindrical pipe = 28 m
Radius (r) of circular end of pipe = 5/2 = 2.5 cm = 0.025m
CSA of cylindrical pipe = 2πrh
= ( 2 x 22/7 x 0.025 x 28) m2
= 4.4 m2
The area of the radiating surface of the system is 4.4 m2.
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Answered
Given,
Length of cylindrical pipe = 28 m = 2800 cm
Diameter of pipe = 5 cm
So, radius of pipe =\(\cfrac52\) cm
Total radiating surface area = 2πrh
\(=2\times\cfrac{22}7\times52\times\)2800 = 44039.28 cm2
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