The paint in a certain container is sufficient to paint an area equal to 9.375 m^2.

Total surface area of one brick = 2(lb + bh + lh)

= [2(22.5 ×10 + 10 × 7.5 + 22.5 × 7.5)] cm²

= 2(225 + 75 + 168.75) cm²

= (2 × 468.75) cm²

= 937.5 cm²

Let n bricks can be painted out by the paint of the container.

Area of n bricks = (n ×937.5) cm² = 937.5n cm²

Area that can be painted by the paint of the container = 9.375 m² = 93750 cm²

∴ 93750 = 937.5n n = 100

Therefore, 100 bricks can be painted out by the paint of the container.

Let the number of bricks be equal to x of dimension 22.5 cm x 10 cm x 7.5 cm which can be painted out of the given container.

Surface area of 1 brick 

= 2(l x b + b x h + h x l)

= 2(22.5 x 10 + 10 x 7.5 + 7.5 x 22.5) cm²

= 2(225 + 75 + 168.75) cm²

= 2 x 468.75 cm²

= 937.5 cm²

According to question

x x 937.5 cm² = 9.375 m²

1 m² = 10000 cm²

⇒ x x 937.5 cm² = 9.375 x 10000 cm²

⇒ x = \(\frac { 9.375\times10000 }{ 937.5 }\)

⇒ x = 100

Hence, required number of bricks = 100.