State which of the following statements are true and which are false. Justify your answer.
State which of the following statements are true and which are false. Justify your answer.
(i) 37 ∉ {x | x has exactly two positive factors}
(ii) 28 ∈ {y | the sum of the all positive factors of y is 2y}
(iii) 7,747 ∈ {t | t is a multiple of 37}
3 Answers
(i) False
Since, 37 has exactly two positive factors, 1 and 37, 37 belongs to the set.
(ii) True
Since, the sum of positive factors of 28
= 1 + 2 + 4 + 7 + 14 + 28
= 56 = 2(28)
(iii) False
7,747 is not a multiple of 37.
(i) The factors of 35 are 1, 5, 7 and 35. So, 35 is an element of the set. Hence, statement is true.
(ii) The factors of 128 hre 1,2,4, 8, 16, 32, 64 and 128.
Sum of factors = 1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 = 255 * 2 x 128 Hence, statement is false.
(iii) We have, x4 – 5x3 + 2x2 – 112x + 6 = 0 Forx = 3, we have
(3)4 – 5(3)3 + 2(3)2 – 112(3) + 6 = 0
=> 81 – 135 + 18-336 + 6 = 0
=> -346 = 0, which is not true.
So 3 is not an element of the set
Hence, statement is true
iv) 496 = 24 x 31
So, the factors of 496 are 1, 2, 4, 8, 16, 31, 62,124, 248 and 496.
Sum of factors = 1 +2 + 4 + 8+ 16 + 31 + 62 + 124 + 248 + 496 = 992 = 2(496)
So, 496 is the element of the set Hence, statement is false
(i) True
According to the question,
35 ∈ {x | x has exactly four positive factors}
The possible positive factors of 35 = 1, 5, 7, 35
35 belongs to given set
Since, 35 has exactly four positive factors
⇒ The given statement 35 ∈ {x | x has exactly four positive factors} is true.
(ii) False
According to the question,
128 ∈ {y | the sum of all the positive factors of y is 2y}
The possible positive factors of 128 are 1, 2, 4, 8, 16, 32, 64, 128
The sum of them
= 1 + 2 + 4 + 8 + 16 + 32 + 64 + 128
= 255
2y = 2 × 128 = 256
Since, the sum of all the positive factors of y is not equal to 2y
128 does not belong to given set
⇒ The given statement 128 ∈ {y | the sum of all the positive factors of y is 2y} is false.
(iii) True
According to the question,
3 ∉ {x | x4 – 5x3 + 2x2 – 112x + 6 = 0}
x4 – 5x3 + 2x2 – 112x + 6 = 0
On putting x = 3 in LHS:
(3)4 – 5(3)3 + 2(3)2 – 112(3) + 6
= 81 – 135 + 18 – 336 + 6
= –366
≠ 0
So, 3 does not belong to given set
⇒ The given statement 3 ∉ {x | x4 – 5x3 + 2x2 – 112x + 6 = 0} is true.
(iv) False
According to the question,
496 ∉ {y | the sum of all the positive factors of y is 2y}
The possible positive factors of 496 are 1, 2, 4, 8, 16, 31, 62, 124, 248, 496
The sum of them
= 1 + 2 + 4 + 8 + 16 + 31 + 62 + 124 + 248 + 496
= 996
2y = 2 × 496 = 992
Since, the sum of all the positive factors of y is equal to 2y
496 belongs to given set
⇒ The given statement 496 ∉ {y | the sum of all the positive factors of y is 2y} is false.