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A game consists of tossing a one rupee coin 3 times and noting its outcome each time. Hanif wins if all the tosses give the same result i.e., three heads or three tails, and loses otherwise. Calculate the probability that Hanif will lose the game.

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2 Answers

The possible outcomes are

{HHH, TTT, HHT, HTH, THH, TTH, THT, HTT}

Number of total possible outcomes = 8

Number of favourable outcomes = 2 {i.e., TTT and HHH} 

P(Hanif will win the game) = 2/8 = 1/4

P (Hanif will lose the game) = 1-1/4 = 3/4

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Total number of outcomes = (HHH),(HHT),(HTH),(THH),(TTH),(TTT),(THT),(HTT)

Given: Hanif loses if there are different coins = 8 – 2 = 6

For Hanif to lose the game, there are 6 possible chances

P(probability that Hanif will lose the game) = 6/8

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