Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively.
Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 m2 of area is painted. How many cans of paint will she need to paint the room?
4 views
1 Answers
Given that,
Length (l) = 15 m, breadth (b) = 10 m, height (h) = 7 m
Area of the hall to be painted = Area of the wall + Area of the ceiling
= 2h (l + b) + lb
= [2(7) (15 + 10) + 15 ×10] m2
= [14(25) + 150] m2
= 500 m2
It is given that 100 m2 area can be painted from each can.
Number of cans required to paint an area of 500 m2 = 500/100 = 5
Hence, 5 cans are required to paint the walls and the ceiling of the cuboidal hall.
4 views
Answered