In a class, there are 18 girls and 16 boys. The class teacher wants to choose one pupil for class monitor.

Total no. of possible outcomes = 34 (18 girls, 16 boys)

(i) E ⟶ event of getting girl name

No. of favorable outcomes = 18 (18 girls)

Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes) = 18/34 = 9/17

(ii) E ⟶ event of getting boy name

No. of favorable outcomes = 16 (16 boys)

P(E) = 16/34 = 8/17

Given: In a class there are 18 girls and 16 boys, the class teacher wants to choose one name. The class teacher writes all pupils’ name on a card and puts them in basket and mixes well thoroughly. A child picks one card

Required to find: The probability that the name written on the card is

(i) The name of a girl

(ii) The name of a boy

Total number of students in the class = 18 + 16 = 34

(i) The names of a girl are 18, so the number of favourable cases is 18

We know that, Probability = Number of favourable outcomes/ Total number of outcomes

Thus, the probability of getting a name of girl on the card = 18/34 = 9/17

(ii) The names of a boy are 16, so the number of favourable cases is 16

We know that, Probability = Number of favourable outcomes/ Total number of outcomes

Thus, the probability of getting a name of boy on the card = 16/34 = 8/17

Total number of possible outcomes, n(S) = 34 

(i) Number of favorable outcomes, 

n(E) = 18

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{18}{34}\) = \(\frac{9}{17}\)

(ii) Number of favorable outcomes, 

n(E) = 16

 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{16}{34}\) = \(\frac{8}{17}\)