In a lottery of 50 tickets numbered 1 to 50, one ticket is drawn. Find the probability that the drawn ticket bears a prime number.

Total no. of possible outcomes = 50 {1, 2, 3, …. , 50}

E⟶ event of getting a prime no.

No. of favourable outcomes = 15

{2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47}

Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes)

i.e. P(E) = 15/50 = 3/10

Given: Tickets are marked numbers from 1 to 50. And, one ticket is drawn at random.

Required to find: Probability of getting a prime number on the drawn ticket

Total number of tickets is 50.

Tickets which are number as prime number are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47

Total number of tickets marked as prime is 15.

We know that Probability = Number of favourable outcomes/ Total number of outcomes

Thus, the probability of getting a prime number on the ticket = 15/50 = 3/10