A polygon has prime number of sides. Its number of sides is equal to the sum of the two least consecutive primes. The number of diagonals of the polygon is

(A) 4    (B) 5    (C) 7   (D) 10

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2 Answers

The correct answer is (B) 5

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(B) 5

The two least consecutive prime numbers are, 2 and 3

Sum of two numbers = 2 + 3 = 5

By using formula = n(n – 3)/2

= 5(5 – 3)/2

= (5 × 2)/2

= 10/2

= 5

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