The lid of a rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of the tape required?

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2 Answers

Total length of tape required = Perimeter of rectangle 

= 2 ( length + breadth) 

= 2 ( 40 + 10) 

= 2 x 50 

= 100 cm = 1 m 

Thus, the total length of tape required is 100 cm or 1 m.

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Length (l) of rectangular box = 40 cm

Breadth (b) of rectangular box = 10 cm

Length o f tape required = perimeter of rectangular box

= 2 ( l + b)

= 2(40 + 10) = 100 cm

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