Two compounds 'A' and 'B' have the same molecular formula C3H6O2. One of them reacts with sodium metal and NaHCO3
Two compounds 'A' and 'B' have the same molecular formula C3H6O2. One of them reacts with sodium metal and NaHCO3 to liberate H2 gas and a gas 'C', respectively. 'C' turns lime water milky. The other compound does not react with either Na metal or NaHCO3 but undergoes saponification to give sodium salt of a carboxylic acid and wood spirit 'D'. Identify A,B, C and D.
1 Answers
Two possible compounds with molecular formula C3H6O2 are propanoic acid (CH3CH2COOH) and methyl acetate (CH3COOCH3). The propanoic acid reacts with Na metal to give sodium propanoate and H2 gas and with NaHCO3, it gives CO2 gas which turns lime water milky. Methyl acetate on saponification gives sodium acetate and wood spirit i.e., methanol.
Thus,
A is propanoic acid
B is methyl acetate
C is carbon dioxide
D is methanol