Explain the action of dilute hydrochloric acid on the following with chemical equation : (i) magnesium ribbon
Explain the action of dilute hydrochloric acid on the following with chemical equation :
(i) magnesium ribbon
(ii) sodium hydroxide
(iii) crushed egg shells
1 Answers
(i) Mg + 2HCI → MgCl2 + H2
Hydrogen gas is produced.
(ii) HCl + NaOH→ NaCl + H2O
Neutralisation reaction
(iii) 2HCl(aq) + CaCO3(s)→CaCl2 (aq)+ H2O + CO2
Calcium chloride is formed.
Detailed Answer:
(i) Dilute hydrochloric acid reacts with magnesium to form magnesium chloride and H2 gas is liberated.
Mg(s) + 2HCl(aq)→MgCl2(aq) + H2(g)
(ii) sodium hydroxide is a neutralisation reaction. Sodium chloride salt and water are formed,Reaction between dilute hydrochloric acid and
NaOH(aq) + HCI(aq)→NaCl(aq) + H2O(l)
(iii) Dilute hydrochloric acid dissolves the CaCO3 and makes the shell soft.Egg shells are made of calcium carbonate, CaCO3.
CaCO3(s) + HCI(aq)→ CaCl2 + CO2(g) + H2O(l)
(Crushed egg shell)