A rod of length L and mass M is pulled by a force F1 at its one end.
A rod of length L and mass M is pulled by a force F1 at its one end. Find tension at a distance y from the end where F1 acts.
(A) F1(1 -y/L)
(B) F1(y/L)
(C) F1(1 + y/L)
(D) None of these
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(A) F1(1 -y/L)
Explanation:
acceleration of string =F/M,
mass of portion of string between distance y and other end of string=M(1-y/L).
tension at distance y=M(1-y/L)F/M
=F(1-y/L)
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