Three students are picked at random from a school having a total of 1000 students.
Three students are picked at random from a school having a total of 1000 students. The probability that these three students will have identical date and month of their birth, is
(a) 3/1000 (b) 3/365 (c) 1/(365)2 (d) None of these
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(c) For 1st student, Probability of selecting any one day as his birthday =365/365 =1
Now, the remaining two students to be selected must have same day as their birthday as for the 1st student. Probability of rest two students, having the same
birthday as that of the 1st student = 1/365 x 1/365
Hence, required probability = 1 x 1/(365)2 = 1/(365)2
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