In a p-n junction, the depletion region is 400 nm wide and an electric field of 5 x 10^5 V/m exists in it.
In a p-n junction, the depletion region is 400 nm wide and an electric field of 5 x 105 V/m exists in it. (a) Find the height of the potential barrier, (b) What should be the minimum kinetic energy of a conduction electron which can diffuse from the n-side to the p-side ?
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Depletion region ‘d’ = 400 nm = 4 x10–7 m
Electric field E = 5 x105 V/m
a) Potential barrier V = E x d = 0.2 V
b) Kinetic energy required = Potential barrier x e = 0.2 eV [Where e = Charge of electron]
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