An experimenter's diary reads as follows: "a charged particle is projected in a magnetic field

Monjur Alahi

An experimenter's diary reads as follows: "a charged particle is projected in a magnetic field of (7.0 vector i - 3.0 vector j) x 10-3T. The acceleration of the particle is found to be (---vector i + 7.0 vector j) x 10-6m/s2''. The number to the left of vector i in the last expression was not readable. What can this number be?


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Salim Ahmed Kawsar

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vector B = (7.0i – 3.0j) × 10–3T

vector a = acceleration = (---i + 7j) × 10–6m/s2

Let the gap be x.

Since vector B and vector a are always perpendicular

vector B x vector a = 0

=> (7x × 10–3 × 10–6 – 3 × 10–3 7 × 10–6) = 0

=> 7x – 21 = 0 => x = 3

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