Find out frequency & wave length of a photon emitted during a transition from n=5 to n=2 in H atom.
Find out frequency & wave length of a photon emitted during a transition from n=5 to n=2 in H atom.
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∆ E= 2.18x 10-18(1/n1 2 – 1/n2 2 )
= 2.18x 10-18(1/52 – 1/22 )
= -4.58 x 10-19 J
Frequency= ∆ E/h
= 4.58 x 10-19 J/6.626 x 10-34 Hz
=6.91 x 1014 Hz
Wave length= C/V0
=3x108 /6.91x1014
=434 nm
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