Calculate the weight of carbon monoxide having same number of oxygen atoms as are present in 88 g of carbon dioxide.
Calculate the weight of carbon monoxide having same number of oxygen atoms as are present in 88 g of carbon dioxide.
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Molecular mass of CO2 = 12 + 2 x 16 = 44
1mol of CO2 = 44 g
44 g of CO2 contain = 6.022 x 1023 molecules
88 g of CO2 contain = 6.022x1023x 88/44
= 12.046 x 1023 molecules
Each molecule of CO2 contain 2 oxygen atoms
No. of oxygen atoms in 12.046 x 1023 molecules of CO2
= 2 x 12.046 x 1023 = 2.4092 x 1024
Now, we have to calculate the mass of CO containing 2.4092 x 1024 atoms of oxygen.
Mass of CO containing 6.022 x 1023 oxygen atoms = 28 g.
Mass of CO containing 2.4092 x 1023 oxygen atoms = 28/6.022x1023 x 2.4092x1024 = 112 g
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