A solution is 25% H2O, 25% C2 H5 OH and 50% acetic acid by mass. Calculate mole fraction of each component.
A solution is 25% H2O, 25% C2 H5 OH and 50% acetic acid by mass. Calculate mole fraction of each component.
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Let the total mass of solution = 100g
Mass of water = 25g
Mass of C2 H5 OH = 25g
Mass of acetic acid = 50 g
nH2o = 25/18 = 1.388
nC2 H5 OH = 25/46 = 0.543
nC H3CO OH = 50/60 = 0.833
total number of moles = 1.388+0.543+0.833 = 2.764
mole fraction of H2O = 1.3888/2.764 = 0.502
mole fraction of C2H5OH = 0.543/2.764 = 0.196
mole fraction of CH3COOH = 0.8333/2.764 = 0.302
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