Pure water vapour is trapped in a vessel of volume 10 cm3 . The relative humidity is 40%. The vapour is compressed slowly and isothermally. Find the volume of the vapour at which it will start condensing.

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1 Answers

RH=VP/SVP

The point where the vapour starts condensing, VP = SVP
We know P1V1 = P2V2
RH SVP × 10 = SVP × V2 => V2 = 10RH => 10 × 0.4 = 4 cm3

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