The pressure of a gas changes linearly with volume from 10kPa, 200cc to 50kPa, 50cc.

Question

The pressure of a gas changes linearly with volume from 10kPa, 200cc to 50kPa, 50cc.

The pressure of a gas changes linearly with volume from 10kPa, 200cc to 50kPa, 50cc. (a) Calculate the work done by the gas. (b) If no heat is supplied or extracted from the gas, what is the change in the internal energy of the gas?

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

P₁ = 10 kpa = 10 × 10³pa. P₂= 50 × 10³pa. v₁ = 200cc. v₂ = 50cc
(i) Work done on the gas = 1/2(10 + 50) x 10³(50 - 200) x 10⁶ = – 4.5J
(ii) dQ = 0 => 0 = du + dw => du = – dw = 4.5J

5 views Answered 2023-02-05 15:29