A proton and an electron have same velocity. Which one has greater de-Broglie wavelength and why?

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2 Answers

de Broglie wavelength (λ) is given as
λ = h/mv
Given vp =ve
where vp = velocity of proton
ve = velocity of electron
Since mp > me
From the given relation
λ ∝1/m, hence λp < λe
Thus, electron has greater de Broglie wavelength, if accelerated with same speed.

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λ = h/mv

here v → same

∴ λ ∝ 1/m

As we know mp > me ∴ λp < λe

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