Calculate the amount of work done in rotating a dipole, of dipole moment 3 x 10^-8cm,
Calculate the amount of work done in rotating a dipole, of dipole moment 3 x 10-8cm, from its position of stable equilibrium to the position of unstable equilibrium, in a uniform electric field of intensity 104N/C.
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P = 3 x 10-8cm ; E =104N/C
At stable equilibrium (θ1 ) = 0°
At unstable equilibrium (θ2) =180°
Work done in rotating dipole is given by:
W = PE (cosθ1 - cosθ2 )
= (3 x 10-8) (104) [cos0º - cos180º]
= 3 x10-4 [1 - (- 1)]
W = 6 x 10-8J
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