How does the fringe width of interference fringes change, when the whole apparatus of Young’s experiment is kept in a liquid of refractive index 1.3?
How does the fringe width of interference fringes change, when the whole apparatus of Young’s experiment is kept in a liquid of refractive index 1.3?
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Fringe width, β = Dλ/d => β ∝ λ for same D and d. When the whole apparatus is immersed in a transparent liquid of refractive index n =1×3, the wavelength decreases to λ = λ/n = λ/1.3. so, fringe width decreases to 1/1.3 time.
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